x^2+119x-3600=0

Solution for x^2+119x-3600=0 equation:

x^2+119x-3600=0

a = 1; b = 119; c = -3600;
Δ = b2-4ac
Δ = 1192-4·1·(-3600)
Δ = 28561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28561}=169$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(119)-169}{2*1}=\frac{-288}{2}
=-144
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(119)+169}{2*1}=\frac{50}{2}
=25
$